Question

Triangle PQR ~ triangle ABC, area of triangle PQR = 27cm^2, BC = 10cm, area of triangle ABC = 75cm^2, then QR=

Answer 1

hii dear!!!

here,

triangle ABC is similar to triangle PQR.

now,

according to the theorem of area of similar triangles and their sides,

∆PQR=QR^2

∆ABC= BC^2

now, substituting values,

27=QR^2

75=(10)^2

27=QR^2

75=100

100×27=QR^2

75

4×27= QR^2

3

4×9= QR^2

36=QR^2

√36=QR

6=QR

hope this helps!!!❤✌☺...good night

Answer 2

Answer:

In similar triangles, ratio of areas is equal to the ratio of the squares of their corresponding sides.