Question

triangle RHP~triangle NED, NE is 7 cm and angle D is 30 degree and angle N is 20 degree and HP/ED=4/5 then construct triangle RHP and NED​

Answer 1

Answer :-

∆RHP ~ ∆NED

so,

→ ∠R = ∠N = 20°

→ ∠P = ∠D = 30°

→ ∠H = ∠E = 180° - (20° + 30°) = 130° { By angle sum property.)

also,

→ HP / ED = 4/5

then,

→ RH / NE = 4/5

→ RH/7 = 4/5

→ RH = (7*4)/5

→ RH = 5.6 cm .

now, Steps of construction :-

1. Draw a line segment RH = 5.6 cm.
2. Draw angles ∠RHX = 130° and ∠HRY = 20° with the help of protractor .
3. The rays HX and RY intersect at vertex P .
4. Join RP and HP .
5. ∆RHP is our required triangle .

similarly,

1. Draw a line segment NE = 7 cm.
2. Draw angles ∠NEA = 130° and ∠ENB = 20° with the help of protractor .
3. The rays EA and NB intersect at vertex D .
4. Join ND and ED .
5. ∆NED is our required triangle .

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