Triangle RPQ is right Angled at Q if pQ is 5cm and RQ is 10cm find cos square and tanR and sinp*cosp
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Given : Triangle RPQ is right Angled at Q . PQ = 5 cm , RQ = 10 cm
To Find : Cos² R , Tan R , SinP.CosP
Solution:
Triangle RPQ is right Angled at Q
PQ = 5 cm
RQ = 10 cm
PR² = PQ² + RQ²
=> PR² = 5² + 10²
=> PR² = 125
=> PR = 5√5 cm
Cos R = RQ/PR
=> CosR = 10/5√5
=> Cos R = 2/√5
=>Cos² R = 4/5
Tan R = PQ/QR
=> Tan R = 5/10
=> Tan R = 1/2
Sin P = PQ / PR
Cos P = QR / PR
=> SinP.CosP = (PQ . QR ) / PR²
=> SinP.CosP = (5 . 10 ) / 125
=> SinP.CosP = 2/5
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Answer:
super answer sir I got full in test exam
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