Question

Triangle side of 20cm 24cm and 25 cm Then find the area how h​

Answer 1

ANSWER✔

$\large\underline\bold{GIVEN,}$

$\sf\therefore taking\:A,B,C \: as \: a \:sides \: of\: a \: triangle,$

$\sf\dashrightarrow AB=20cm=a$

$\sf\dashrightarrow BC=24cm=b$

$\sf\dashrightarrow AC=25cm=c$

$\large\underline\bold{TO\:FIND,}$

$\sf\dashrightarrow \:AREA\:OF\:TRIANGLE$

✯FORMULA IN USE,

$\large{\boxed{\bf{ \star\:\: \sqrt{s(s-a)(s-b)(s-c)} \:\: \star}}}$

WE KNOW,

$\sf\dashrightarrow S= \dfrac{a+b+c}{2}$

$\sf\implies s= \dfrac{20+24+25}{2}$

$\sf\implies s= \dfrac{69}{2}$

$\sf\implies s=\cancel \dfrac{69}{2}$

$\sf\implies 34.5cm$

$\rm{\boxed{\bf{ \star\:\: s=34.5\:\: \star}}}$

$\large\underline\bold{SOLUTION,}$

$\sf\dashrightarrow s=34.5$

$\sf\dashrightarrow 20cm=a$

$\sf\dashrightarrow 24cm=b$

$\sf\dashrightarrow 25cm=c$

$\sf\implies \sqrt{(34.5)(34.5-20)(34.5-24)(34.5-25)}$

$\sf\implies \sqrt{(34.5)(14.5)(10.5)(9.5)}$

$\sf\implies \sqrt{(500.25) \times (99.75)}$

$\sf\implies \sqrt{49899.8375}$

$\sf\implies \sqrt{49899.8375} cm^{2}$

$\sf\implies 223.38 cm^{-2}$

$\large{\boxed{\bf{ \star\:\: 223.38 cm^{-2} \:\: \star}}}$

$\large\underline\bold{HENCE,\:THE\:AREA\:OF\:TRIANGLE\:IS\: 223.38cm^{-2}}$

__________________

Answer 2

Step-by-step explanation:

U CAN ANSWER THIS BY USING THE HERONS FORMULA

$area \: \sqrt{s(s - a)(s - b)(s - c)}$

$perimeter = 20 + 24 + 25 = 69$

$semi \: perimeter \: or \: s \: = \frac{69}{2} = 34.5$

$\sqrt{34.5(34.5 - 20)(34.5 - 24)(34.5 - 25)}$

$\sqrt{34.5(14.5)(10.5)(9.5)}$

$\sqrt{49899.9375}$

$= 223.38 \:cm {s}^{ - 2}$