Question

triangle
Theorem 8.9 : The line segment joining the mid-points of two sides of a
is parallel to the third side.
You can prove this theorem using the following
А
clue:
Observe Fig 8.25 in which E and Fare mid-points
F
of AB and AC respectively and CD || BA.
E
A AEF = A CDF (ASA Rule)
So, EF = DF and BE = AE = DC (Why?) B В
(C
Therefore, BCDE is a parallelogram. (Why?)
Fig. 8.25
This gives EF || BC.
D
In this case, also note that EF
-
1
ED =
BC.
2
2.
Can you state the converse of Theorem 8.9? Is the converse true?
You will see that converse of the above theorem is also true which is stated
below:​

Answer 1

Answer:

mathematics Hain triangle chapter ka

Step-by-step explanation:

ye mujhe bhi nhi samjh aa Raha hain

Answer 2

Answer:

refer photo to get your answer