Triangle XYZ is translated 4 units up and 3 units left to yield ΔX′Y′Z′. What is the distance between any two corresponding points on ΔXYZ and ΔX′Y′Z′?
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Thank you for asking this question. Here is your answer:
We will use the Pythagoras Theorem here:
and we will get this:
c² = a² + b²
and here a and b are the legs and c is the hypotenuse.
After putting values in that we will get:
c² = 3² + 4²
= 9 + 16
= 25
c = √25
= 5 units
so the final answer for this question is 5 units.
If there is any confusion please to leave a comment below.
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