Question

Triangle XYZ is translated 4 units up and 3 units left to yield ΔXYZ. What is the distance between any two corresponding points on ΔXYZ and ΔXYZ′?

Answer 1

Answer:

Distance between any two corresponding points = 5 units

Step-by-step explanation:

In this translation, Each point of the triangle has covered two dimensional distances.

   Vertical Upward Distance = 4 units  (Perpendicular)

Horizontal left-side Distance = 3 units  (Base)

The required distance is between Two Corresponding points and these points will be the endpoints of the Hypotenuse in any case, so the distance will be equal to

 H^2 = B^2 + P^2

 H^2 = 3^2 + 4^2

  H^2 = 9 + 16

   H^2 =  25

       H = 5 units

   

Answer 2

Answer:

5 units

Step-by-step explanation:

A triangle translated

Given, a triangle XYZ translated to a new location with upward distance of 4 units and horizontal left side 3 units.

The distance between any two corresponding points will be the hypotenuse of horizontal and vertical translation.

H2 = B2 + P2

H2 = 32 + 42

H2 = 9 + 16

H2 =  25

H= 5