Question

Triangle xyz, xy=yz and angle Z=40 °, then find angle X and angle y​

Answer 1

Answer:

$\blue{\mathfrak{\underline{\large{Given}}}:} \\ xy = yz \\ \angle z = 40 \degree \\ \blue{\mathfrak{\underline{\large{To \: find}}}:} \\ find \: \angle x \: and \: \angle y \\ \blue{\mathfrak{\underline{\large{Finding}}}:} \\ since, \: side \: xy = yz \\ \color{blue}\underline{according \: to \: statement} \\ angle \: opposite \: to \: equal \: sides \: are \: equal \\ hence, \: \angle x = \angle z = 40 \degree \\ sum \: of \: the \: angles \: of \: triangle = 180 \degree \\ \angle x + \angle y + \angle z = 180 \degree \\ 40 \degree + \angle y + 40 \degree = 180 \degree \\ \angle y + 80 \degree = 180 \degree \\ \boxed{\boxed{\angle y = 100 \degree}} \\ \\ \red{\mathfrak{ \large{\underline{{Hope \: It \: Helps \: You}}}}} \\ \blue{\mathfrak{ \large{\underline{{Mark \: Me \: Brainliest}}}}}$