Question

triangle XYZ, Y =90 degree, Z =60 degree, ZX =12 cm. Find YZ
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Answer 1

Answer:

a+b+c+d=180^

90+60+12+d=180^

162+d=180^

d=180^-162

d=17^

Step-by-step explanation:

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Answer 2

Given:-

• ∠Y of triangle XYZ is 90°.
• ∠Z of triangle XYZ is 60°.
• Side ZX is 12 cm.

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To find:-

• Side YZ of triangle XYZ.

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Solution:-

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☘$\large \tt \: cos \: θ = \frac{Base}{Hypotenuse}$

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$\implies \tt \: cos \: 60\degree = \frac{Base}{Hypotenuse} --(1)$

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☆ Base = YZ

☆ Hypotenuse = ZX = 12 cm

☆ Cos 60° = $\frac{1}{</strong><strong>2</strong><strong>}$

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So, Put the values in equation (1)

$\implies \tt \: \frac{1}{2} = \frac{YZ}{12}$

• Cross multiply

$\implies \tt \: 12 = 2 \times YZ$

$\implies \tt \: \frac{12}{2} = YZ$

$\implies \tt \: 6 = YZ$

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Therefore, YZ is 6 cm.

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More ratio's:-

☘$\large \tt \: sin \: θ = \frac{Perpendicular}{Hypotenuse}$

☘$\large \tt \: tan \: θ = \frac{Perpendicular}{Base}$

☘$\large \tt \: Cot \: θ = \frac{Base}{Perpendicular}$

☘$\large \tt \: cosec \: θ = \frac{Hypotenuse}{Perpendicular}$

☘$\large \tt sec\: θ = \frac{Hypotenuse}{Base}$