Question

TriangleABC is right angled at c. If AC=5cm , BC=12cm , Find The length of AB

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Answer 1

Answer:

AB=13cm

Step-by-step explanation:

by Pythagoras theorem

AB^2=AC^2+BC^2

AB^2=5^2+12^2

AB^2=25+144

AB^2=169

AB=13cm

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Answer 2

Answer:

13 cm

Step-by-step explanation:

$given \: right \: angle \: triangle \: acb \\ using \: pythgoras \: theorem \: \\ \sqrt{ b {}^{2} + p {}^{2}} = 12h {}^{2} \\ here \: b(base) = cb = 12cm \\ \: \: p(perpendicular \: height) ac = 5cm \\ h(hypotenuse) = ab = {?} \\ now \: h { }^{2} = \sqrt{b {}^{2} + p {}^{2}} \\ \: \: \: = \sqrt{12 {}^{2} + 5 {}^{2} } cm \\ = \sqrt{144 + 25}cm \\ = \sqrt{169}cm \\ = 13cm$