trianglePQR and triangleXYZ are such that PQ||XY, PR||XZ and PQ=XY. if PR=XZ, then show that area of (trianglePQR)=area of(triangleXYZ)
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Answered by
4
Infact both the triangles are totally same.Hence same area.
See:-
PQ II XY , PRIIXZ ,and the mentioned sides are of equal length.
Lines are parallel and intersecting at a common point subtend the same angle at the points of intersection.Lines being of equl length..their bases - QP and YZ are also of equal length..Hence both the triangles are same and hence equal areas..
See:-
PQ II XY , PRIIXZ ,and the mentioned sides are of equal length.
Lines are parallel and intersecting at a common point subtend the same angle at the points of intersection.Lines being of equl length..their bases - QP and YZ are also of equal length..Hence both the triangles are same and hence equal areas..
Answered by
5
In ΔPQR and XYZ
PQ = XY
PR = XZ
∠Q = ∠Y (QX as transversal)
∴ΔPQR =Δ XYZ
⇒ar(PQR) = ar (XYZ)
PQ = XY
PR = XZ
∠Q = ∠Y (QX as transversal)
∴ΔPQR =Δ XYZ
⇒ar(PQR) = ar (XYZ)
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