Question

Triangles ABC and DBC are on the same base BC with A,D on opposite sides of BC if area of ABC is equal to DBC prove that BC bisects AD.

No spamming pls and explain with the help of diagram​

Answer 1

Answer:

you got the solution from the picture

you got the solution from the pictureI hope it will help u

Answer 2

Construction: Draw AL ⊥ BC and DM ⊥ BC.  Proof : ar(∆ABC) = ar(∆DBC) [Given]  ⇒ BC x AL /2 = BC x DM/2 ⇒ AL = DM ....(i)  Now in ∆s OAL and OMD  AL = DM [From (i)]  ⇒ ∠ALO = ∠DMO [Each = 900 ]  ⇒ ∠AOL = ∠MOD [Vert. opp. ∠s]  ⇒ ∠OAL = ∠ODM [Third angles of the triangles]  ∴ ∆OAL ≅ ∆OMD [By ASA]  ∴ OA = OD [By cpctc]  i.e., BC bisects AD