Triangles ABC and DCB are right angled at A and D
respectivly and AC DB, prone that ABC= ADC .
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Step-by-step explanation:
angle A=angleD(each 90°)-------(1)
AC=DB(given) -------(2)
BC=CB(side opposite to equal angles) -----(3)
so frm SAS congruence ∆ABC=~∆DCB......
FRM CPCT ABC = DCB
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