Question

Triangles (Class 10)


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Answer 1

Answer:

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b) x = ac/b+c

Explanation:

In △KPN and △KLM, we have

   ∠KNP=∠KML= 56∘  [Given]

    ∠K= ∠K                           [Common]

∴  △KNP ∼ △KML        [By AA-criterion of similarity]

⇒   KN/KM =  NP/ML [∵ Corresponding sides of similar triangles are proportional]  

⇒    c/b+c  =  x/a

⇒x = ac/b+c

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Answer 2

Answer:(b) x =ac/b+c

Explanation:

Given ∠M=56° and ∠N=56°

In ΔKNQ and ΔKML

∠KNQ = ∠KML (56°)

∠NKQ = ∠MKL

By AA similarity criterion ΔKNQ ~ ΔKML

KN/QN=KM/LM (cpst)

i.e c/x=c+b/a

1/x=c+b/ac

∴ x=ac/b+c