Question

triangles D is a point on hypotenuse AC of ABC,such that BD AC, DM BC DN AB prove that DM2=DN.MC

Answer 1

Answer:

Step-by-step explanation:

Now, if we take

In AMB and BMC we get

BM=BM. [ common ]

AM=MC. [ Given]

So, by SS criteria of similarity

AMB is similar to BMC

So,

DM/DN=MC/DM

>>DM²=DN*MC

HENCE PROVED

Hope it will help you