Math, asked by createrafted, 9 months ago

•Triangles on the same base (or equal bases) and between

the same parallels are equal in area. (with proof)​

Answers

Answered by Ravi942004
1

Answer:

A (triangle1)÷A (triangle2)=base1×height1÷

base2×height2

as triangle have equal base an they are between parallel line so there height is equal

A (triangle1)÷A (triangle2)=1

therefore A (triangle1)=A (triangle2)

Similar questions
Math, 9 months ago