Question

triangular board has side 30cm 20cm and 45 cm find the cost of painting the board on both the sides of rupees 5 per CM square using herons formula​

Answer 1

Answer:

Hello There,

Your answer is = Rupees 571,484.375

Step-by-step explanation:

Heron's Formula =

$\sqrt{s(s - a)(s - b)(s - c)}$

s = (30 + 20 + 45) / 2

s = 47.5

47.5 - 30 = 17.5

47.5 - 20 = 27.5

47.5 - 45 = 2.5

47.5 × 17.5 × 27.5 × 2.5

= 57,148.4375

Area of one side of the board = 57,148.4375

Area of 2 sides of the board = 2 × 57,148.4375

= 114,296.875

Cost of painting at 5 Rupees per cm^2

= 114,296.875 × 5

= Rupees 571,484.375.

This is your answer.