Question

triangular field of dimensions 13m 14m and 15m . if the cost of painting the wall is rs 2000 per m^2 find total cost of painting​

Answer 1

Answer:

a=13m

b=14m

c=15m

SEMI-PERIMETER OF THE TRIANGLE,s=(13+14+15)/2=21m

USING HERON'S FORMULA,

AREA=√[s(s-a)(s-b)(s-c)]

=√[21*(21-13)*(21-14)*(21-15)]

=√[21*8*7*6]

=√7056

AREA =84 m^{2}m

2

since,1 m^{2}m

2

costs Rs.2000 per year

therefore,84m^{2}m

2

will cost 2000*84,that is Rs168000 per year

therefore for 6 months,i.e.1/2 year,it will cost

=168000*\frac{1}{2}

2

1

=Rs.84000