triangular park ABC has sides 120m, 80m and 50m. A gardener Dhania has to put a
fence all around it and also plant grass inside. How much area does she need to plant?
Find the cost of fencing it with barbed wire at the rate of 20 per metre leaving a space
3m wide for a gate on one side.
Answers
ANSWER
here, a=120m,
b=80m,
c=50m
and, s=2
a+b+c = 2
250
=125
Area she need to plant grass =
s(s−a)(s−b)(s−c)= 125(125−120)(125−80)(125−50)
=375
15m^2
cost of fencing =[(a+b+c)−3].20
=[250−3].20
=Rs4940
Step-by-step explanation:
For finding the area of the park, we have
2s= 50m + 80m + 120m =250m
i.e., s= 125m
Now, s - a = [125-120] m = 5m [a],
s - b = [125-80] m = 45m [b],
s - c = [125-50] m = 75m [c].
Therefore, area of the park = √s[s-a] [s-b] [s-c]
= √125 × 5 × 45 × 75 m²
= 375√15 m²
Also, perimeter of the park = AB + BC + CA = 250m
Therefore, length of the wire needed for fencing = 250m-3m[ to be left for the gate]
= 247m
So the length of wire required is 247m
And so the cost of fencing= Rs20 × 247
= Rs 4940
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