Biology, asked by mylswamydeva, 8 months ago

triangular park ABC has sides 120m, 80m and 50m. A gardener Dhania has to put a
fence all around it and also plant grass inside. How much area does she need to plant?
Find the cost of fencing it with barbed wire at the rate of 20 per metre leaving a space
3m wide for a gate on one side.

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Answers

Answered by johaarmonu12
4

ANSWER

here, a=120m,

b=80m,

c=50m

and, s=2

a+b+c = 2

250

=125

Area she need to plant grass =

s(s−a)(s−b)(s−c)= 125(125−120)(125−80)(125−50)

=375

15m^2

cost of fencing =[(a+b+c)−3].20

=[250−3].20

=Rs4940

Answered by Kim1Teahyung
0

Step-by-step explanation:

For finding the area of the park, we have

               2s= 50m + 80m + 120m =250m

i.e.,             s= 125m

Now,          s - a = [125-120] m = 5m [a],

                  s - b = [125-80] m = 45m [b],

                  s - c = [125-50] m = 75m [c].

Therefore, area of the park = √s[s-a] [s-b] [s-c]

                                              = √125 × 5 × 45 × 75 m²

                                              = 375√15 m²

Also, perimeter of the park = AB + BC + CA = 250m

Therefore, length of the wire needed for fencing = 250m-3m[ to be left for the gate]

                                                                                 = 247m

So the length of wire required is 247m

And so the cost of fencing= Rs20 × 247

                                            = Rs 4940

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