Math, asked by shwetaabhi1987, 26 days ago

triangular plot is given in the ratio 6:8:10 and its perimeter is 340 m.Find the area of the plot in m².​

Answers

Answered by TwilightShine
7

Answer :-

  • The area of the triangular plot is 11304.2998 m².

To find :-

  • The area of the triangular plot.

Step-by-step explanation :-

  • It is given that the three sides of the triangular plot are in the ratio 6 : 8 : 10.

Let :-

  • The sides be 6x, 8x and 10x.

We know that :-

 \underline{ \boxed{ \sf Perimeter \:  of   \: a \: triangle = Sum \:  of  \: all  \: sides}}

Here,

  • Perimeter = 340 m.

Therefore,

 \longrightarrow \tt 6x + 8x + 10x = 340

 \longrightarrow \tt 24x = 340

 \longrightarrow \tt{\cancel{\dfrac{340}{24}}}

 \tt \longrightarrow x = 14.16

 \\

Hence, the sides of the triangle are :-

 \bf 6x = 6 \times 14.16 = 84.96 \: m

 \bf 8x = 8 \times 14.16 = 113.28 \: m

 \bf 10x = 10 \times 14.16 = 141.6 \: m

____________________________

  • For finding the area of the triangular plot, first we need to find out it's semi perimeter.

We know that :-

\underline{\boxed{\sf{Semi-perimeter = \dfrac{Sum \: of \: three \: sides}{2}}}}

Here,

  • The sides are 84.96 m, 113.28 m and 141.6 m.

Therefore,

\sf{Semi-perimeter = \dfrac{84.96 + 113.28 + 141.6}{2}}

\sf{ Semi-perimeter = \dfrac{84.96 + 113.28 + 141.6}{2}}

 \sf{ Semi-perimeter = \cancel{ \dfrac{340}{2}}}

 \sf{Semi-perimeter = 170 \: m}

 \\

Now, we know that :-

 \underline{\boxed{\sf{Area \: of \:a \: triangle = \sqrt{s(s - a) (s - b) (s - c}}}}

Here,

  • Semi-perimeter = 170 m.
  • The sides are 84.96 m, 113.28 m and 141.6 m.

Therefore,

 \sf{ Area = \sqrt{s(s - a) (s - b) (s - c)}}

 \sf{ Area = \sqrt{170(170 - 84.96) (170 - 113.28) (170 - 141.16)}}

 \sf{ Area = \sqrt{170(155.84)(85.04)(56.72)}}

\sf Area = \sqrt{127787194.22}

\sf Area = 11304.2998 \: m^2

 \\

Hence,

  • The area of the triangular plot is 127787194.22 m².

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