Question

Trick to find hybridisation of coordination compound

Answer 1

ANSWER:

STERIC NUMBER=( TOTAL NO OF ELECTRON)/8

QUOTIENT=NO OF BOND PAIR

(REMAINDER)/2= NO OF LONE PAIR

STERIC NO= QUOTIENT+ REMAINDER

example: XeF6

Total No of electron(a)=50

a/8= 8*6+2

so

Bond Pair=6

lone pair=(2/2)=1

so

STERIC number=6+1=7

Hybridization=sp3d3