Question

Trignomentary ke anupato ko sinA,secA aur tanA ko cotA ke pado me byakt karo​

Answer 1

Answer:

sinA in term of cotA

cosec²A -cot²A = 1

cosec²A= 1+cot²A

sinA= 1/√1+cot²A

secA in term of cotA

sec²A - tan²A = 1

sec²A = 1 + tan²A

sec²A = 1 + 1/ cot²A

sec²A = (cot²A + 1)/cot²A

secA= √(cot²A+1)/cotA

tanA = 1/cotA