Math, asked by Sahanagouda, 1 year ago

Trignometrey tan^3/ 1+tan^2 + cot^3/1+cot^2 = sec × cosec - 2 sin × cos
LHS = RHS class 10th
Plz answer for this i 'll put u in brainst ​

Answers

Answered by arjun6068
13

Tan^3A / Sec^2A + Cot^3A / Cosec^2A 

= (sin^3A/cos^3A) / (1 / Cos^2A) + (Cos^3A/Sin^3A) / (1 / Sin^2A) 

= Sin^3A/CosA + Cos^3A/SinA 

= (Sin^4A + Cos^4A) / SinA.CosA 

= [ (Sin^2A + Cos^2A)^2 - 2Sin^2A.Cos^2A] / SinA.CosA 

= ( 1- 2Sin^A.Cos^A)/ SinA.CosA 

RHS = SecA CosecA - 2sinAcosA 

= 1/CosA . 1/SinA - 2SinACosA 

= (1 - Sin^2A.Cos^2A) / sinAcosA 

Hence LHS = RHS (PROVED)

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Sahanagouda: Tq
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Answered by aditya99975
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