trignometry mein ye variable (k) kyu lete h jo bad mein cut jata h.agar k na le to
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Yes , even if u don't take the variable k , u can solve the answer correctly but since trigonometry is all about ratios , you have to take variable k.
ex - Let there be a triangle ABC
P = 4 , H = 5 , B = 3
tan = P/B = 4/3
Consider another triangle DEF
P = 2(4) , B = 2(3) , H = 2(5)
tan = P/B = 8/6 = 4/3
See here
The value of tan for both triangles is same = 4/3
But both triangles are not congruent.
Because there exists an constant (k=2) which cancels out.
Yes , even if u don't take the variable k , u can solve the answer correctly but since trigonometry is all about ratios , you have to take variable k.
ex - Let there be a triangle ABC
P = 4 , H = 5 , B = 3
tan = P/B = 4/3
Consider another triangle DEF
P = 2(4) , B = 2(3) , H = 2(5)
tan = P/B = 8/6 = 4/3
See here
The value of tan for both triangles is same = 4/3
But both triangles are not congruent.
Because there exists an constant (k=2) which cancels out.
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