Question

trignometry please ans Question 9th​

Answer 1

Answer:—

• Option (A) :- 1

Step By Step Explaination:—

Given : (sec∅ - cos∅)(cosec∅-sin∅)(cot∅+tan∅).(1)

As we know,

• sec∅ = 1/cos∅
• cosec∅= 1/sin∅
• cot∅= cos∅/sin∅
• tan∅= sin∅/cos∅

putting these values into (1)

(1/cos∅-cos∅)(1/sin∅-sin∅)(cos∅/sin∅+sin∅/cos∅)

→(1-cos²∅/cos∅)(1-sin²∅/sin∅)(cos²∅+sin²∅/sin∅cos∅)

[ °•° sin²∅ = 1-cos²∅ , cos²∅= 1-sin²∅]

→ sin²∅/cos∅(cos²∅/sin∅)(1/sin∅cos∅)

[°•° sin²∅+cos²∅= 1]

→ sin²∅cos²∅/sin²∅cos²∅

1.

Answer 2

Answer:

1

Step-by-step explanation:

Put the vale of Thita=45°

(√2-1/√2)(√2-1/√2)(1+1)

1/√2×1/√2×2

2/2 cancell out

=1