Question

trigonometric functions of-135°​

Answer 1

Answer:

sin (- 135°)= – sin 135°= – sin (1 × 90°+ 45°) = – cos 45° = – 1√2.

cos (- 135°)= cos 135°= cos (1 × 90°+ 45°) = – sin 45°= – 1√2.

tan (- 135°) = – tan 135° = – tan ( 1 × 90° + 45°) = – (- cot 45°) = 1.

csc (- 135°)= – csc 135°= – csc (1 × 90°+ 45°)= – sec 45° = – √