trigonometric ratio of 30 degree and 60 degree
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Therefore, ∠POB = 30° + 30° = 60°; which shows that each angel of triangle OPQ is 60° . Hence ∆OPQ is equilateral. Therefore, OA = √3a (Since, OA > 0). And cot 30° = 1tan30° = √3
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Therefore, ∠POB = 30° + 30° = 60°; which shows that each angel of triangle OPQ is 60° . Hence ∆OPQ is equilateral. Therefore, OA = √3a (Since, OA > 0). And cot 30° = 1tan30° = √3.
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