Question

Trigonometric Ratios by Construction
paper construct AABC with base BC = 10 cm,
ABC = 35º and ACB = 90°.
(1) Measure AB and AC and record.
(1) Find the values of sin 35°, cos 35º and tan 35° using sides of triangle abc​

Answer 1

Answer:

1) AB=12.21cm AC=7cm

2) Sin 35 = 0.5736

Cos 35 = 0.8192

Tan 35= 0.7002

Step-by-step explanation:

Using Trignometry.

Answer 2

AB = 7cm. and AC= 12.21 cm. and sin 35° = perpendicular/hypotenuse = 7/12.21=0.57 cm.

cos 35º= base/hypotenuse= 10/12.21= 0.82 cm. and tan 35°= perpendicular/ base= 7/ 10= 0.7 cm.

Step-by-step explanation:

Triangle ABC with base BC = 10 cm, angle ABC = 35º and angle ACB = 90° is constructed.

Now, in this triangle, clearly, the given side BC is the base of the right-angled triangle. Then, we need to find the measure of the other two sides that is the hypotenuse and the perpendicular.

Then, from the construction of the triangle, the perpendicular = 7cm.

Then, by applying the Pythagoras theorem,

Square of the hypotenuse= Square of the perpendicular + square of the base.

Then, square of the hypotenuse= $10^{2}+7^{2}$

                                                     = 100 + 49

                                                     = 149

Therefore, hypotenuse

=

$\sqrt{149}\\ =12.21 cm.$

Then, sin 35° = perpendicular/hypotenuse = 7/12.21=0.57 cm.

cos 35º= base/hypotenuse= 10/12.21= 0.82 cm. and tan 35°= perpendicular/ base= 7/ 10= 0.7 cm.

Hence, AB = 7cm. and AC= 12.21 cm. and sin 35° = perpendicular/hypotenuse = 7/12.21=0.57 cm.

cos 35º= base/hypotenuse= 10/12.21= 0.82 cm. and tan 35°= perpendicular/ base= 7/ 10= 0.7 cm.

Learn more here

https://brainly.in/question/16352667

Learn more

https://brainly.in/question/22279668