Question

Trigonometric Ratios of Compound Angles
1. sin (A + B) = sin A cos B+cos A sin B and
sin (A - B) = sin A cos B-cos A sin B.
2. cos (A + B) = cos A cos B - sin A sin B and
cos (A - B) = cos A cos B + sin A sin B.
tan A + tan B
3. tan(A + B) =-
1 -tan Atan B
tan A -tan B
tan (A-B) =
1+tan Atan B
Explain it in clear sence​

Answer 1

Step-by-step explanation:

1. sin (A + B) = sin A cos B+cos A sin B and

sin (A - B) = sin A cos B-cos A sin B.

2. cos (A + B) = cos A cos B - sin A sin B and

cos (A - B) = cos A cos B + sin A sin B.

3. tan(A + B) =-

1 -tan Atan B

tan A -tan B

tan (A-B) =

1+tan Atan B