Question

Trigonometry,.......

Answer 1

sinA-2sin^3A÷2cos^3A-cosA=tanA

sinA(1-2sin^2A)÷cosA(2cos^2A-1)
tanA(sin^2A+cos^2A-2sin^2A)÷(2cos^2A-sin^2A-cos^2A)

tanA(cos^2A-sin^2A)÷(cos^2A-sin^2A)

tanA. proved

Answer 2

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