Question

TRIGONOMETRY A wheel of a motor is rotating at 1200 r.p.m. If the radius of the wheel is 35 cm, what
linear distance does a point of its rim traverse in 30 seconds?​

Answer 1

Answer:

α=t2−t1ω2−ω1

ω1=602π×1200=40π;ω2=602π×4500=150π

α=10110πrad/sec2

Now π radian =180∘

∴1 rad=π180∘ degree

∴ α=π11π×180 degrees/sec2=1980 degress/sec2