Question

Trigonometry ( basic )

Answer both question..
With steps ​

Answer 1

Answer:

#BAL #AnswerWithQuality

Step-by-step explanation:

$\frac{1 - {tan}^{2}60 }{1 + {tan}^{2}60 } = cosx \\ = > \frac{1 - 3}{1 + 3} = cosx \\ = > \frac{ - 2}{2} = cosx \\ = > - 1 = cosx \\ = > cos(180) = cosx \\ = > x = 180$

[tan 60° = √3] and [-1 = cos 180°]

_____________________________

log[(secA + tanA)(secA - tanA)]

= log[sec²A - tan²A]. [ (a +b)(a-b) = a²-b²]

= log1. [ log 1 = 0]

= 0

________________

Answer 2

Answer:

i

Step-by-step explanation:

please mark my ans as brainleast