Question

Trigonometry board question if you can answer this you’re a genius

Answer 1

Heyaa..!!

Here's your answer mate..

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$we \: know \: that \: \sin(90 - theta) = \cos(theta) \\ thus... { \cos(67) }^{2} - \ { \sin }^{2} (90 - 67) \\ { \cos}^{2}67 - { \ \cos }^{2} 67 = 0$
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HOPE IT HELPS

@Rêyaañ11

Answer 2

Hey this is your answer