Question

Trigonometry challengers !

Here is an interesting Question . Plz solve it -,-

If ,
$cos( \alpha ) = \dfrac{1}{2} \bigg(x + \dfrac{1}{x} \bigg)$
$cos( \beta ) = \dfrac{1}{2} \bigg(y + \dfrac{1}{y} \bigg)$
then evaluate cos(alpha-beta)

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Answer 1

Answer:

1 by 2 and 1 by 1 this is the answer for it

Answer 2

Answer:

hey here is your solution in above pics

pls mark it as brainliest