trigonometry chapter plzz answer me
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tan 60 = AC / DC
sqrt(3) = 60 / DC
DC = 60 / sqrt (3) - - - - sqrt(3) = 1.732
DC = 34.642 m (horizontal dist.)
tan 30 = AB / BE
1 / sqrt(3) = AB / 34.64
AB = 34.642 / sqrt(3)
AB = approx. 20 m
height of lamppost = AC - AB
= 34.64 - 20
= 14.64 m
sqrt(3) = 60 / DC
DC = 60 / sqrt (3) - - - - sqrt(3) = 1.732
DC = 34.642 m (horizontal dist.)
tan 30 = AB / BE
1 / sqrt(3) = AB / 34.64
AB = 34.642 / sqrt(3)
AB = approx. 20 m
height of lamppost = AC - AB
= 34.64 - 20
= 14.64 m
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