Question

Trigonometry class 10!

Answer 1

Answer:

17/5

Step-by-step explanation:

given:-

cotA = 12/15

As we know,

By the formula,

cosec²A - cot²A = 1

=> cosec²A = 1+cot²A

=> cosec²A = 1+(12/15)²

=> cosec²A = 1+144/225 = (25+144)/25 = 169/25

=> cosec A = √(169/25) = 13/5

Also,

sinA = 1/cosecA = 1÷(13/5) = 5/13

Now, by the formula,

sin²A + cos²A = 1

=> cos²A = 1-sin²A

=> cos²A = 1-(5/13)² = 1-25/169

=> cos²A = (169-25)/169 = 144/164

=> cos A = √(144/169) = 12/13

ATQ,

(sinA + cosA) × cosecA = (5/13 + 12/13) × 13/5

(sinA + cosA) × cosecA = 17/13 × 13/5 = 17/5

Answer 2

Answer:

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