Question

Trigonometry class 11. Please help if you know. it's very important.​

Answer 1

Answer:

sin20 sin40 sin60 sin80

We know that

sinA sin(60−A) sin(60+A)=

4

1

sin3A

∴sin60×sin20 sin(60−20)sin(60+20)

=

2

3

×sin(20×3)×

4

1

=

2

3

×sin60×

4

1

=

4

1

×

2

3

×

2

3

=

16

3

Step-by-step explanation:

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Answer 2

Answer:

Question: 1

Add the following:

(i) 3x and 7x

(ii) -5xy and 9xy

Solution:

We have

(i) 3x + 7x = (3 + 7) x = 10x

(ii) -5xy + 9xy = (-5 + 9)xy = 4xy

Question: 2

Simplify each of the following:

(i) 7x3y +9yx3

(ii) 12a2b + 3ba2

Solution:

Simplifying the given expressions, we have

(i) 7x3y + 9yx3 = (7 + 9)x3y = 16x3y

(ii) 12a2b + 3ba2 = (12 + 3)a2b =15a2b