Math, asked by Ghost010, 11 months ago

Trigonometry !!!!

Find the value of sin 135° ?​

Answers

Answered by Anonymous
6

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= sin 135°

= sin (90+45°)

= sin 90.cos45+cos90.sin45

= 1 × \displaystyle\frac {1}{\sqrt{2}}+ 0×\displaystyle\frac {1}{\sqrt{2}}

= \displaystyle\frac {1}{\sqrt{2}}

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