Question

trigonometry please solve it​

Answer 1

$\frac{ \cos(x) }{1 + \sin(x) } \times \frac{1 - \sin(x) }{1 - \sin(x) } = \frac{ \cos(x) \times (1 - \sin(x) }{1 - \sin( {x}^{2} ) }$

$\frac{ \cos(x)(1 - \sin(x) }{ \cos( {x}^{2} ) } = \frac{1 - \sin(x) }{ \cos(x) } = \frac{1}{ \cos(x) } - \frac{ \sin(x) }{ \cos(x) } = \sec(x) - \tan(x)$

answer=secx

Answer 2

Hey Mate!

Hope this pic helps you...

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