Math, asked by ItsmeShiddat, 10 months ago

Trigonometry
Please solve this​

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Answered by RNR4Nikitha
1

Answer:

2( \cos ^{4} 60 +  \sin ^{4} 30) - ( \tan ^{2} 60 +  \cot^{2}45) + 3 \sec ^{2} 60 \\ 2(( \frac{1}{2} ) ^{4}  + ( \frac{1}{2} ) ^{4}) - ( \sqrt{3} ^{2}  +  {1}^{2} ) + 3(2) ^{2} \\ 2( \frac{1}{16}  +  \frac{1}{16} ) - (3 + 1) + 3(4) \\ 2( \frac{1 + 1}{16} ) - 4 + 12 \\ 2( \frac{2}{16} ) - 4 + 12 \\ 2( \frac{1}{8} ) - 4 + 12 \\  \frac{1}{4}  - 4 + 12 \\  \frac{1 - 4(4) + 12(4)}{4}  \\  \frac{1 - 16 + 48}{4}  \\  \frac{49 - 16}{4}  =  \frac{33}{4}

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