Question

trigonometry :plz answer it​

Answer 1

One side of a triangle is 6 centimetres and the angles at its ends are 40° and 65°. Calculate its area.

cos 40 = A D 6 AD6 AD = 6 x cos 40 = 6 x 0.7660 = 4.6 tan 40 = B D A D = B D 4.6 BDAD=BD4.6 BD = 4.6 x tan 40 = 4.6 x 0.8391 = 3.86 tan 75 = B D D C = 3.86 D C BDDC=3.86DC DC x tan 75 = 3.86 DC = 3.86 t a n 74 = 3.86 3.7321 = 1.03 3.86tan74=3.863.7321=1.03 AC = 4.6 + 1.03 = 5.63 Area of the triangle = 1 2 12 x AC x BD = 1 2 12 x 5.63 x 3.86 = 10.87

hope that helps