Math, asked by Suja2005, 4 months ago

trigonometry proof question​

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Answered by kavyasingh40
3

Answer:

answer is 1, the solution is as follows kindly mention the 'given' and 'to find' in your answer

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Answered by HetJoshi1684
1

 \sin(theta)  +  \sin^{2} (theta)  = 1

1 =  \sin^{2} (theta)  +  \cos^{2} (theta)

therefore

 \sin(theta)  +  \sin^{2} (theta)  =  \sin^{2} (theta)  +  \cos^{2} (theta)

Eliminating sin2 theta from both sides

 \sin(theta)  =  \cos^{2} (theta)

put this into the first equation and you will get

 \sin(theta)  +  \sin^{2} (theta)  = 1

 \cos ^{2} (theta)  +  \cos^{4} (theta)  = 1

Answer is 1

Step-by-step explanation:

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