Trigonometry Prove SinA/1+cosA + TanA = SecA
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Let’s see. We can start by writing it out, and then manipulating each side to make them equal.
sinA∗tanA+cosA=secA
I usually convert things to sin and cos just to make it more familiar.
sinA∗sinAcosA+cosA=1cosA
Now you can reduce the fraction on the left.
sin2AcosA+cosA=1cosA
Now you can manipulate cosA to get a common denominator
sin2AcosA+cos2AcosA=1cosA
Now that you have a common denominator, you can combine the fractions.
sin2A+cos2AcosA=1cosA
And now since you (should) know that sin2A+cos2A=1, you can substitute that expression for 1, leaving you with:
1cosA=1cosA
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