Math, asked by nirushrestha546, 17 days ago

trigonometry(Pythagoras)

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Answered by KINGHEMANTH
0

Answer:

de ^{2}  = ef ^{2}  + df ^{2}

de =x

ef = 2 root 3 cm

df = 2 cm

Step-by-step explanation:

substitute in formula

DE²= DF² + EF²

X = (2)² + (2 root 3)²

x = 4 + 6 root 9

x = 4 + 6 × 3

4 + 18

x = 22

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