Trigonometry Question
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(Sinx/cosx) cosx / sin^3x+sinxcosx
Take sinx as common in denominator
(Sinx/cosx) cosx / sinx(sin^2x+cos^2x). (:.sin^2x+cos^2x=1)
(sinx/cosx) cosx / sinx
Cancel all the terms and the answer is 1.
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Answer:
formula =
1. sin²A + cos²A = 1
2. tanA = sinA/cosA
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