Question

trigonometry question

Answer 1

$3 \sin( \frac{\pi}{6} ) \sec( \frac{\pi}{3} ) - 4 \sin( \frac{5\pi}{6} ) \cot( \frac{\pi}{4} ) \\ = 3 \sin(30) \sec(60) - 4 \sin(150) \cot(45) \\ = 3 \times \frac{1}{2} \times2 - 4 \times \frac{1}{2} \times 1 \\ = 3 - 2 \\ = 1$