Question

trigonometry question solved in copy

Answer 1

sin80°+sin50° = 2sin[(80°+50°)/2]cos[(80°-50°)/2]      

 [ using sinC+sinD = 2sin[(C+D)/2]cos[(C-D)/2] ]

⇒ sin80°+sin50° = 2sin(130°/2)cos(30°/2)

⇒ sin80°+sin50° = 2sin65°cos15°

So value of α = 65° and value of β = 15°