History, asked by vipulraj9, 2 months ago


Trigonometry Ratio...​

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Answered by pari25325
1

Answer:

{[cos A(cos A)]+[1+sin A(1+sin A)]}÷1+sinA(cos A)

[cos^{2}A+(1+sinA)^{2}]÷(1+sin A cos A)

[cos^2A+1+2sinA+sin^2A]÷ (1+sin A) cos A

(1+1+2sinA)÷(1+sin A) cos A

(2+2sinA)÷(1+sin A) cos A

2(1+sin A)÷(1+sin A) cos A

2÷cosA

2secA

Answered by Anonymous
0

Answer:

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