Question

trigonometry ratio question 4 please somebody help

Answer 1

Here is the answer. Hope you were helped
Cheers mate. :^)

Answer 2

1st approach:-

sin²60° + cos²(3x-9°) =1,

(√3/2)² + cos²(3x-9)=1,

3/4 + cos²(3x-9)=1,

then

cos²(3x-9)=1-3/4,

cos²(3x-9)=(4-3)/4,

cos²(3x-9)=1/4,

cos(3x-9)=√(1/4),

cos(3x-9)=1/2,

then

cos(3x-9)=cos60°,

(3x-9)=60,

hence

3x=60+9,

3x=69,

x=69/3,

x=23,


2nd approach:-


since

sin²60° + cos²(3x-9)=1,

and we know that
sin²@+cos²@=1,

then

we can say that

(3x-9)=60,

3x=60+9,

3x=69,

x=69/3,

x=23