Question

trigonometry ratios ​

Answer 1

Answer:

sin0°=0 cos0°=1

sin30°=1/2 cos30°=√3/2

sin45°=1/√2 cos45°=1/√2

sin60°=√3/2 cos60°=1/2

sin90°=1 cos90°=0

Answer 2

Table of trigonometry is given :

$\red{ \boxed{\sf{Trigonometric\: Ratios\: Table :-}}}$

$\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\boxed{\begin{array}{ |c |c|c|c|c|c|} \bf\angle A & \bf{0}^{ \circ} & \bf{30}^{ \circ} & \bf{45}^{ \circ} & \bf{60}^{ \circ} & \bf{90}^{ \circ} \\ \\ \rm sin A & 0 & \dfrac{1}{2}& \dfrac{1}{ \sqrt{2} } & \dfrac{ \sqrt{3} }{2} &1 \\ \\ \rm cos \: A & 1 & \dfrac{ \sqrt{3} }{2}& \dfrac{1}{ \sqrt{2} } & \dfrac{1}{2} &0 \\ \\ \rm tan A & 0 & \dfrac{1}{ \sqrt{3} }& 1 & \sqrt{3} & \rm \infty \\ \\ \rm cosec A & \rm \infty & 2& \sqrt{2} & \dfrac{2}{ \sqrt{3} } &1 \\ \\ \rm sec A & 1 & \dfrac{2}{ \sqrt{3} }& \sqrt{2} & 2 & \rm \infty\: \\ \\ \rm cot A & \rm \infty & \sqrt{3} & 1 & \dfrac{1}{ \sqrt{3} } & 0 \end{array}}}\end{gathered}\end{gathered} \end{gathered} \end{gathered}$

$\purple{\rule{51pt}{8pt}}\red{\rule{51pt}{8pt}}\pink{\rule{51pt}{8pt}}\blue{\rule{51pt}{8pt}}$

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